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Boofz

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The Uzumaki

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Rand al'Thor

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19 posters

Go to page : 1, 2

If you enjoy maths:

Jon

Jon: Sponsor; Posts : 13685
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Post n°1

If you enjoy maths:

by Jon 2013-10-27, 15:23

A friend just proved to me that 0.9 recurring is equal to 1.

x = 0.99999...
∴ 10x = 9.99999...
9x = 10x - x
∴ 9x = 9.99999... - 0.99999...
∴ 9x = 9
∴ x = 1

Therefore proving that there must be an end to an infinite amount of digits. My mind has been blown.

Lelz

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Post n°2

Re: If you enjoy maths:

by Lelz 2013-10-27, 15:26

2+2=5

it's true

someone proved it

really

ceck it.

Rand al'Thor

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Post n°3

Re: If you enjoy maths:

by Rand al'Thor 2013-10-27, 15:59

I swear that is part of GCSE Razz

Razz

There's also:
1 = 0.3333333…
3
3 = 0.9999999…
3
∴ 1 = 0.9999999…

Firefury54: Sponsor; Posts : 4033
Join date : 2012-06-24
Age : 110
Location : United States

Post n°4

Re: If you enjoy maths:

by Firefury54 2013-10-27, 16:52

Jon wrote:A friend just proved to me that 0.9 recurring is equal to 1.

x = 0.99999...
∴ 10x = 9.99999...
9x = 10x - x
∴ 9x = 9.99999... - 0.99999...
∴ 9x = 9
∴ x = 1

Therefore proving that there must be an end to an infinite amount of digits. My mind has been blown.

Your error lies in the fact that you are trying to find x when you already know the answer. In actuality, the equation you used would progress as follows:

9x = 10x - x
9x = 9x
x = 1

Therefore, x would have been 1 regardless of you plugging in an arbitrary number for just 2 out of 3 x's (which fails to follow any mathematical rationale.). Tell your friend to forfeit his manhood and go back to the 5th grade.

Rand al'Thor wrote:I swear that is part of GCSE

There's also:
1 = 0.3333333…
3
3 = 0.9999999…
3
∴ 1 = 0.9999999…

This, on the other hand, is a valid mathematical proof ... *mind blown*

Andrew: VIP; Posts : 5628
Join date : 2011-07-01
Age : 31
Location : Connecticut

Post n°5

Re: If you enjoy maths:

by Andrew 2013-10-27, 16:58

http://en.wikipedia.org/wiki/Fermat%27s_Last_Theorem

The Uzumaki

The Uzumaki: VIP; Posts : 9689
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Age : 28
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Post n°6

Re: If you enjoy maths:

by The Uzumaki 2013-10-27, 17:11

Firefury54 wrote:

Jon wrote:A friend just proved to me that 0.9 recurring is equal to 1.

x = 0.99999...
∴ 10x = 9.99999...
9x = 10x - x
∴ 9x = 9.99999... - 0.99999...
∴ 9x = 9
∴ x = 1

Therefore proving that there must be an end to an infinite amount of digits. My mind has been blown.

Your error lies in the fact that you are trying to find x when you already know the answer. In actuality, the equation you used would progress as follows:

9x = 10x - x
9x = 9x
x = 1

Therefore, x would have been 1 regardless of you plugging in an arbitrary number for just 2 out of 3 x's (which fails to follow any mathematical rationale.). Tell your friend to forfeit his manhood and go back to the 5th grade.

Rand al'Thor wrote:I swear that is part of GCSE

There's also:
1 = 0.3333333…
3
3 = 0.9999999…
3
∴ 1 = 0.9999999…

This, on the other hand, is a valid mathematical proof ... *mind blown*

That was....

Simply beautiful

G: Highroller; Posts : 10394
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Age : 24
Location : DM

Post n°7

Re: If you enjoy maths:

by G 2013-10-27, 17:28

11+1=12

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Post n°8

Re: If you enjoy maths:

by CM 2013-10-27, 18:05

Over Living wrote:11+1=12

And 12-1=11 o.O

11-1=10
10-1=9

11-9=2

11-9=
11-9
9-11 OOOO.oooo

Jon

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Post n°9

Re: If you enjoy maths:

by Jon 2013-10-27, 19:07

Firefury54 wrote:

Jon wrote:A friend just proved to me that 0.9 recurring is equal to 1.

x = 0.99999...
∴ 10x = 9.99999...
9x = 10x - x
∴ 9x = 9.99999... - 0.99999...
∴ 9x = 9
∴ x = 1

Therefore proving that there must be an end to an infinite amount of digits. My mind has been blown.

Your error lies in the fact that you are trying to find x when you already know the answer. In actuality, the equation you used would progress as follows:

9x = 10x - x
9x = 9x
x = 1

Therefore, x would have been 1 regardless of you plugging in an arbitrary number for just 2 out of 3 x's (which fails to follow any mathematical rationale.). Tell your friend to forfeit his manhood and go back to the 5th grade.

Rand al'Thor wrote:I swear that is part of GCSE

There's also:
1 = 0.3333333…
3
3 = 0.9999999…
3
∴ 1 = 0.9999999…

This, on the other hand, is a valid mathematical proof ... *mind blown*

ummm... that is valid proof.

Bf: Honorary Member; Posts : 6451
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Age : 20
Location : Majed's room in Sam's house

Post n°10

Re: If you enjoy maths:

by Bf 2013-10-27, 19:43

Lol, I remember learning this in Calc senior year. #mindblown

Slash: Global Mod; Posts : 10756
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Age : 27
Location : Ali's computer

Post n°11

Re: If you enjoy maths:

by Slash 2013-10-27, 20:12

Fuck me sideways

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Age : 31
Location : California, USA

Post n°12

Re: If you enjoy maths:

by Daft Punk 2013-10-27, 20:34

A friend of mine proved that 9 = 5 using i in a formula. Our calculus professor couldn't explain why it didn't work. I'll see if I can have him send it to me, its a lot to do with how i is cyclical, but i don't remember it exactly.

Firefury54: Sponsor; Posts : 4033
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Age : 110
Location : United States

Post n°13

Re: If you enjoy maths:

by Firefury54 2013-10-27, 20:54

Jon wrote:

Firefury54 wrote:

Jon wrote:A friend just proved to me that 0.9 recurring is equal to 1.

x = 0.99999...
∴ 10x = 9.99999...
9x = 10x - x
∴ 9x = 9.99999... - 0.99999...
∴ 9x = 9
∴ x = 1

Therefore proving that there must be an end to an infinite amount of digits. My mind has been blown.

Your error lies in the fact that you are trying to find x when you already know the answer. In actuality, the equation you used would progress as follows:

9x = 10x - x
9x = 9x
x = 1

Therefore, x would have been 1 regardless of you plugging in an arbitrary number for just 2 out of 3 x's (which fails to follow any mathematical rationale.). Tell your friend to forfeit his manhood and go back to the 5th grade.

Rand al'Thor wrote:I swear that is part of GCSE

There's also:
1 = 0.3333333…
3
3 = 0.9999999…
3
∴ 1 = 0.9999999…

This, on the other hand, is a valid mathematical proof ... *mind blown*

ummm... that is valid proof.

Then maybe you care to enlighten me because I still fail to see how this is a valid proof. Even if we played it out the way you explained it; it doesn't make sense. Let me begin from where the misunderstanding was identified:

9x = 10x - x
x = 0.99999...
9(0.999...) = 10(0.999...) - (0.999...)
8.999... = 9.999 ... - 0.999 ....
8.999... ≠ 9

This is why your proof doesn't make sense to me. You cannot simply plug in a predetermined value for x for a part of the equation and not the rest ... Why would you solve for "x" when you already decided to use 0.999 ... for x? While it is highly likely that there is a valid proof for your statement, it was not confirmed with the proof your friend used.

Jon

Jon: Sponsor; Posts : 13685
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Age : 27
Location : United Kingdom

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Post n°14

Re: If you enjoy maths:

by Jon 2013-10-27, 20:58

Firefury54 wrote:

Jon wrote:

Firefury54 wrote:

Jon wrote:A friend just proved to me that 0.9 recurring is equal to 1.

x = 0.99999...
∴ 10x = 9.99999...
9x = 10x - x
∴ 9x = 9.99999... - 0.99999...
∴ 9x = 9
∴ x = 1

Therefore proving that there must be an end to an infinite amount of digits. My mind has been blown.

Your error lies in the fact that you are trying to find x when you already know the answer. In actuality, the equation you used would progress as follows:

9x = 10x - x
9x = 9x
x = 1

Therefore, x would have been 1 regardless of you plugging in an arbitrary number for just 2 out of 3 x's (which fails to follow any mathematical rationale.). Tell your friend to forfeit his manhood and go back to the 5th grade.

Rand al'Thor wrote:I swear that is part of GCSE

There's also:
1 = 0.3333333…
3
3 = 0.9999999…
3
∴ 1 = 0.9999999…

This, on the other hand, is a valid mathematical proof ... *mind blown*

ummm... that is valid proof.

Then maybe you care to enlighten me because I still fail to see how this is a valid proof. Even if we played it out the way you explained it; it doesn't make sense. Let me begin from where the misunderstanding was identified:

9x = 10x - x
x = 0.99999...
9(0.999...) = 10(0.999...) - (0.999...)
8.999... = 9.999 ... - 0.999 ....
8.999... ≠ 9

This is why your proof doesn't make sense to me. You cannot simply plug in a predetermined value for x for a part of the equation and not the rest ... Why would you solve for "x" when you already decided to use 0.999 ... for x? While it is highly likely that there is a valid proof for your statement, it was not confirmed with the proof your friend used.

The value that I defined as x is 0.999...
10x-x=9x
10(0.999...)-0.999... = 9x = 9
x=1

Therefore x equals both 0.999... and 1. If 0.999... is equal to 1. Then they are the same. ie. They are equal. I don't know how I can possibly put it any simpler than that. It is proof.

These are the first 4 results when I google'd: "0.999... = 1"
If you enjoy maths: 599ab0eab6f0f884254e9bc3f93963cb

If you enjoy maths: 599ab0eab6f0f884254e9bc3f93963cb

http://en.wikipedia.org/wiki/0.999...

If you enjoy maths: C22c0f63ec1849d5792cee781f7209a6

If you enjoy maths: C22c0f63ec1849d5792cee781f7209a6

http://www.purplemath.com/modules/howcan1.htm

If you enjoy maths: 3a8bd131ddbdf5e1789ffc2d92274f86

If you enjoy maths: 3a8bd131ddbdf5e1789ffc2d92274f86

http://www.math.hmc.edu/funfacts/ffiles/10012.5.shtml

If you enjoy maths: 14426cfe6d54131e201c8547aa426640

If you enjoy maths: 14426cfe6d54131e201c8547aa426640

http://www.mathsisfun.com/9recurring.html

स्वस्ति

स्वस्ति: Member; Posts : 133
Join date : 2013-10-19

Post n°15

Re: If you enjoy maths:

by स्वस्ति 2013-10-27, 21:25

This is why i think math is complete bullshit

The Uzumaki

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Age : 28
Location : Malaysia

Post n°16

Re: If you enjoy maths:

by The Uzumaki 2013-10-27, 21:26

स्वस्ति wrote:This is why i think math is complete bullshit

Why did you delete the earlier post ngawwww

स्वस्ति

स्वस्ति: Member; Posts : 133
Join date : 2013-10-19

Post n°17

Re: If you enjoy maths:

by स्वस्ति 2013-10-27, 21:27

The Uzumaki wrote:

स्वस्ति wrote:This is why i think math is complete bullshit

Why did you delete the earlier post ngawwww

that works the same:

9x = 10x - x
9x = 9x
x = 1

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Age : 110
Location : United States

Post n°18

Re: If you enjoy maths:

by Firefury54 2013-10-27, 21:29

Now, THAT is a valid proof. Thank you. You missed a step and had me confused Razz

Razz

The Uzumaki

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Post n°19

Re: If you enjoy maths:

by The Uzumaki 2013-10-27, 21:29

स्वस्ति wrote:

The Uzumaki wrote:

स्वस्ति wrote:This is why i think math is complete bullshit

Why did you delete the earlier post ngawwww

that works the same:

9x = 10x - x
9x = 9x
x = 1

Lol the answer to that is

1 = 1

Not x = 1

Divide both sides by x

Rand al'Thor

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Post n°20

Re: If you enjoy maths:

by Rand al'Thor 2013-10-27, 21:34

Daft Punk wrote:A friend of mine proved that 9 = 5 using i in a formula. Our calculus professor couldn't explain why it didn't work. I'll see if I can have him send it to me, its a lot to do with how i is cyclical, but i don't remember it exactly.

My Chinese friend showed me this 'proof' using i:

1 = 1^½
= (-1.-1)^½
= (-1)^½(-1)^½
= i²
= -1

lol

Jon

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Post n°21

Re: If you enjoy maths:

by Jon 2013-10-27, 21:39

Rand al'Thor wrote:

Daft Punk wrote:A friend of mine proved that 9 = 5 using i in a formula. Our calculus professor couldn't explain why it didn't work. I'll see if I can have him send it to me, its a lot to do with how i is cyclical, but i don't remember it exactly.

My Chinese friend showed me this 'proof' using i:

1 = 1^½
= (-1.-1)^½
= (-1)^½(-1)^½
= i²
= -1

lol

-1 < 9u²

स्वस्ति

स्वस्ति: Member; Posts : 133
Join date : 2013-10-19

Post n°22

Re: If you enjoy maths:

by स्वस्ति 2013-10-27, 21:46

This one is also making my head hurt: 1=2

a = b.

a + a = a + b

2 x a = a + b.

2 x a × a = a x (a + b)

2 x a x a = a x a + a x b.

2 x a x a - 2 x a x b = a x a - a x b.

2 x (a x a - a × b) = a x a - a x b.

let's say: c = a × a - a × b:

2 × c = c.

so:

2 = 1.

Rand al'Thor

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Post n°23

Re: If you enjoy maths:

by Rand al'Thor 2013-10-27, 21:49

स्वस्ति wrote:This one is also making my head hurt: 1=2

a = b.

a + a = a + b

2 x a = a + b.

2 x a × a = a x (a + b)

2 x a x a = a x a + a x b.

2 x a x a - 2 x a x b = a x a - a x b.

2 x (a x a - a × b) = a x a - a x b.

let's say: c = a × a - a × b:

2 × c = c.

so:

2 = 1.

let's say: c = a × a - a × b:
then, c = 0

2 × c = c.

so:

2 = 1.

And you cannot divide by zero :c

स्वस्ति

स्वस्ति: Member; Posts : 133
Join date : 2013-10-19

Post n°24

Re: If you enjoy maths:

by स्वस्ति 2013-10-27, 22:08

Yes rand!

Ok now without looking it up try this one (don't post the answer, it's quite tricky):

3 guys go to rent a motel room for the night , the desk clerk informs them it will be $30 dollars for the night. They agree and split the cost at $10 per person. The men check into their room and 30 minutes later, the desk clerk realizes that he charged them $5 too much, he sends the bellboy up to the room with 5 -$1 dollars bills as their rebate for overpayment. The men cannot agree on how to evenly split the $5 bucks, one guy suggests that they each take a dollar back and tip the bellboy $2 bucks for bringing it up to them.

Now we come to premise; which leaves each one of the guys paying $9 dollars each for the room; now, if 9x3=27 and they gave the bellboy a $2 dollar tip; bringing the total to 29; where did the other dollar go?

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Post n°25

Re: If you enjoy maths:

by CM 2013-10-27, 22:11

Got through cal 1 senior year with the help of an Asian friend. Seriously.

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Post n°26

Re: If you enjoy maths:

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