Allen

i am not smarter than a fifth grader



#areyousmarterthanafifthgrader

I got 4 pi^3 / e

ez

Needs more unknowns

Iamtaba wrote:I got 4 pi^3 / e

I got this as well.. Slash gave us a multiple choice question for which there is no correct answer... He's as dumb as a fifth grader.

Jon wrote:

Iamtaba wrote:I got 4 pi^3 / e

I got this as well.. Slash gave us a multiple choice question for which there is no correct answer... He's as dumb as a fifth grader.

How'd you two manage to get that?

It's     4    , i.e. the second option.
      e¹¹ π³

Rand al'Thor wrote:

Jon wrote:

Iamtaba wrote:I got 4 pi^3 / e

I got this as well.. Slash gave us a multiple choice question for which there is no correct answer... He's as dumb as a fifth grader.

How'd you two manage to get that?

It's     4    , i.e. the second option.
      e¹¹ π³

4/(e^2)/(pi^3)/(e^4)/(e^5)
= 4/(e^2)/(pi^3)/(e^-1)
=4/(e^2)/(e(pi^3))
=4/e/(pi^3)
=(4 x pi^3)/e

Jon wrote:

Rand al'Thor wrote:

Jon wrote:

Iamtaba wrote:I got 4 pi^3 / e

I got this as well.. Slash gave us a multiple choice question for which there is no correct answer... He's as dumb as a fifth grader.

How'd you two manage to get that?

It's     4    , i.e. the second option.
      e¹¹ π³

4/(e^2)/(pi^3)/(e^4)/(e^5)
= 4/(e^2)/(pi^3)/(e^-1)
=4/(e^2)/(e(pi^3))
=4/e/(pi^3)
=(4 x pi^3)/e

This is so easy...

They seek him here, they seek him there, they seek that Allen everywhere.

Lol. I told Slash that Jon would be one of those people who would get it for sure.

Nevertheless, Rand is correct. Kudos.

Jon wrote:

Rand al'Thor wrote:

Jon wrote:

Iamtaba wrote:I got 4 pi^3 / e

I got this as well.. Slash gave us a multiple choice question for which there is no correct answer... He's as dumb as a fifth grader.

How'd you two manage to get that?

It's     4    , i.e. the second option.
      e¹¹ π³

4/(e^2)/(pi^3)/(e^4)/(e^5)
= 4/(e^2)/(pi^3)/(e^-1)
=4/(e^2)/(e(pi^3))
=4/e/(pi^3)
=(4 x pi^3)/e

The 2nd step is wrong

If you let 4/(e^2)/(pi^3)/(e^4)=x

Then, x/(e^5) would equal to x(e^(-5)).

You'd have to bring it to the very top numerator not the next respective one.

I'd assume however that Rand used wolfram or some other super computer, as he probably would be quick to correct Jon, granted the opportunity.

Who likes a can of worms?

Allen1 wrote:Lol. I told Slash that Jon would be one of those people who would get it for sure.

Nevertheless, Rand is correct. Kudos.

Is that all I get? Kudos? Fk u.

Allen1 wrote:I'd assume however that Rand used wolfram or some other super computer

Does a brain count? I actually studied Maths and Further Maths for A-Level ;_;

I initially ignored the topic as I thought it was someone who'd just found out about e and thought posting about it made them look intelligent. It was only after reading Icy and Jon's posts that I thought I'd check it myself, too.

I don't get the fifth grade reference, though, other than remembering fractions within fractions being really shitty practice our teachers advised us against lower down the school.




For Jon,

mull over
x/x/x
and
x/(x/x)
for a bit.

It's easier to multiply all the divisors first and then consider it with the numerator. Like,

4 * 1 * 1 * 1 * 1 
     e²  π³  e⁴  e⁵
or
4(e^2)^-1(pi^3)^-1(e^4)^-1(e^5)^-1 = 4((e^2)(pi^3)(e^4)(e^5))^-1
                                                     = 4(e^11 * π^3)^-1

Do kids study "E" during 5th grade?

Rand al'Thor wrote:

Allen1 wrote:Lol. I told Slash that Jon would be one of those people who would get it for sure.

Nevertheless, Rand is correct. Kudos.

Is that all I get? Kudos? Fk u.

Allen1 wrote:I'd assume however that Rand used wolfram or some other super computer

Does a brain count? I actually studied Maths and Further Maths for A-Level ;_;

I initially ignored the topic as I thought it was someone who'd just found out about e and thought posting about it made them look intelligent. It was only after reading Icy and Jon's posts that I thought I'd check it myself, too.

I don't get the fifth grade reference, though, other than remembering fractions within fractions being really shitty practice our teachers advised us against lower down the school.




For Jon,

mull over
x/x/x
and
x/(x/x)
for a bit.

It's easier to multiply all the divisors first and then consider it with the numerator. Like,

4 * 1 * 1 * 1 * 1 
     e²  π³  e⁴  e⁵
or
4(e^2)^-1(pi^3)^-1(e^4)^-1(e^5)^-1 = 4((e^2)(pi^3)(e^4)(e^5))^-1
                                                     = 4(e^11 * π^3)^-1

This is so easy how can u get this wrong..?>???

Rand al'Thor wrote:

Allen1 wrote:Lol. I told Slash that Jon would be one of those people who would get it for sure.

Nevertheless, Rand is correct. Kudos.

Is that all I get? Kudos? Fk u.

Allen1 wrote:I'd assume however that Rand used wolfram or some other super computer

Does a brain count? I actually studied Maths and Further Maths for A-Level ;_;

I initially ignored the topic as I thought it was someone who'd just found out about e and thought posting about it made them look intelligent. It was only after reading Icy and Jon's posts that I thought I'd check it myself, too.

I don't get the fifth grade reference, though, other than remembering fractions within fractions being really shitty practice our teachers advised us against lower down the school.




For Jon,

mull over
x/x/x
and
x/(x/x)
for a bit.

It's easier to multiply all the divisors first and then consider it with the numerator. Like,

4 * 1 * 1 * 1 * 1 
     e²  π³  e⁴  e⁵
or
4(e^2)^-1(pi^3)^-1(e^4)^-1(e^5)^-1 = 4((e^2)(pi^3)(e^4)(e^5))^-1
                                                     = 4(e^11 * π^3)^-1

The 5th grade thing is just referential to a bad American TV show.

And this problem wasn't even that bad, I just gave it to Slash just to prove my point that he wasn't very competent at solving fractions - and after he failed two problems my point was proven. Then, he asked me to test him on a topic of his choice for 1m, to which he also answered incorrectly.

As far as the problem, it's more so something that you're expected to be able to solve rather than a testament to your intelligence. Math in the United States and maybe even internationally is taught with a completely flawed approach, just a mental regurgitation of formulas rather than a conceptual mastery of the topic material. That's why you have 17 year olds who aren't able to solve fraction problems.

Allen1 wrote:

Rand al'Thor wrote:

Allen1 wrote:Lol. I told Slash that Jon would be one of those people who would get it for sure.

Nevertheless, Rand is correct. Kudos.

Is that all I get? Kudos? Fk u.

Allen1 wrote:I'd assume however that Rand used wolfram or some other super computer

Does a brain count? I actually studied Maths and Further Maths for A-Level ;_;

I initially ignored the topic as I thought it was someone who'd just found out about e and thought posting about it made them look intelligent. It was only after reading Icy and Jon's posts that I thought I'd check it myself, too.

I don't get the fifth grade reference, though, other than remembering fractions within fractions being really shitty practice our teachers advised us against lower down the school.




For Jon,

mull over
x/x/x
and
x/(x/x)
for a bit.

It's easier to multiply all the divisors first and then consider it with the numerator. Like,

4 * 1 * 1 * 1 * 1 
     e²  π³  e⁴  e⁵
or
4(e^2)^-1(pi^3)^-1(e^4)^-1(e^5)^-1 = 4((e^2)(pi^3)(e^4)(e^5))^-1
                                                     = 4(e^11 * π^3)^-1

The 5th grade thing is just referential to a bad American TV show.

And this problem wasn't even that bad, I just gave it to Slash just to prove my point that he wasn't very competent at solving fractions - and after he failed two problems my point was proven. Then, he asked me to test him on a topic of his choice for 1m, to which he also answered incorrectly.

As far as the problem, it's more so something that you're expected to be able to solve rather than a testament to your intelligence. Math in the United States and maybe even internationally is taught with a completely flawed approach, just a mental regurgitation of formulas rather than a conceptual mastery of the topic material. That's why you have 17 year olds who aren't able to solve fraction problems.

1 + 1 = 1
9   10   21

Paul wrote:

Allen1 wrote:

Rand al'Thor wrote:

Allen1 wrote:Lol. I told Slash that Jon would be one of those people who would get it for sure.

Nevertheless, Rand is correct. Kudos.

Is that all I get? Kudos? Fk u.

Allen1 wrote:I'd assume however that Rand used wolfram or some other super computer

Does a brain count? I actually studied Maths and Further Maths for A-Level ;_;

I initially ignored the topic as I thought it was someone who'd just found out about e and thought posting about it made them look intelligent. It was only after reading Icy and Jon's posts that I thought I'd check it myself, too.

I don't get the fifth grade reference, though, other than remembering fractions within fractions being really shitty practice our teachers advised us against lower down the school.




For Jon,

mull over
x/x/x
and
x/(x/x)
for a bit.

It's easier to multiply all the divisors first and then consider it with the numerator. Like,

4 * 1 * 1 * 1 * 1 
     e²  π³  e⁴  e⁵
or
4(e^2)^-1(pi^3)^-1(e^4)^-1(e^5)^-1 = 4((e^2)(pi^3)(e^4)(e^5))^-1
                                                     = 4(e^11 * π^3)^-1

The 5th grade thing is just referential to a bad American TV show.

And this problem wasn't even that bad, I just gave it to Slash just to prove my point that he wasn't very competent at solving fractions - and after he failed two problems my point was proven. Then, he asked me to test him on a topic of his choice for 1m, to which he also answered incorrectly.

As far as the problem, it's more so something that you're expected to be able to solve rather than a testament to your intelligence. Math in the United States and maybe even internationally is taught with a completely flawed approach, just a mental regurgitation of formulas rather than a conceptual mastery of the topic material. That's why you have 17 year olds who aren't able to solve fraction problems.

1 + 1 = 1
9   10   21

I literally made the same addition joke to a friend of mine.

I think me and jon thought it was like
A
-
B
-
C
-
D


Rather than
A
-
Bcd

Iamtaba wrote:I think me and jon thought it was like
A
-
B
-
C
-
D


Rather than
A
-
Bcd

It is

A
_
B
_
C
_
D

like

Jon wrote:

Rand al'Thor wrote:

Jon wrote:

Iamtaba wrote:I got 4 pi^3 / e

I got this as well.. Slash gave us a multiple choice question for which there is no correct answer... He's as dumb as a fifth grader.

How'd you two manage to get that?

It's     4    , i.e. the second option.
      e¹¹ π³

4/(e^2)/(pi^3)/(e^4)/(e^5)
= 4/(e^2)/(pi^3)/(e^-1)
=4/(e^2)/(e(pi^3))
=4/e/(pi^3)
=(4 x pi^3)/e

Hit this problem into my calculator since I couldn't see anything wrong with my working assuming that my understanding of the problem is correct and both the question and the solution that both icy and I reached is equal to 45.6.

Calculator agrees with me

I actually got the answer Jon got to start with but I did the same mistake, and got to Allen's

Allen's is correct. AKA my second option

gg
g
g
g
gg
jon is not smarter than a 5th grader

Rand al'Thor wrote:
For Jon,

mull over
x/x/x
and
x/(x/x)
for a bit.

mhmm. To use an example, I would have interpreted the question 4/1/2 as four divided by one half which is obviously 8 whereas you'd interpret it as four divided by one, then divided by two which is 2. Admittedly technically speaking I suppose your interpretation is the correct one. I think it's probably the / rather than ÷ that threw me since I envisioned it as a towered fraction. Using the example I used earlier:
_4_
1/2

rather than 4÷1÷2

which I think you would agree would be 8 since it suggests the 1/2 should be performed first though for which there is no technical reason that it should be. Thus officially
_4_
1/2                          

= 2 which is what you did.

Jon wrote:

Rand al'Thor wrote:
For Jon,

mull over
x/x/x
and
x/(x/x)
for a bit.

mhmm. To use an example, I would have interpreted the question 4/1/2 as four divided by one half which is obviously 8 whereas you'd interpret it as four divided by one, then divided by two which is 2. Admittedly technically speaking I suppose your interpretation is the correct one. I think it's probably the / rather than ÷ that threw me since I envisioned it as a towered fraction. Using the example I used earlier:
_4_
1/2

rather than 4÷1÷2

which I think you would agree would be 8 since it suggests the 1/2 should be performed first though for which there is no technical reason that it should be. Thus officially
_4_
1/2                          

= 2  which is what you did.

If you plug it into your calculator, assuming you used parentheses after every term, you should get Rand's answer.

Try plugging it in on Wolframalpha