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+8

Shygodd

Sanne

G

Sand Crawl99 | Z4S

Iamtaba

sai karthik4

Dogs>Cats

The Uzumaki

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k math help

The Uzumaki

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Post n°1

k math help

by The Uzumaki 2013-10-14, 06:03

Question 8 part 1

If possible please include handwritten working (a picture)

Not only the working, but also explaining what is a a convergent

Thanks

https://2img.net/r/ihimizer/img585/241/n0wm.jpg

Edit: I don't understand google's explanation of convergence

Edit : 2 I know convergence now, but still can't do the question Very Happy

Very Happy

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Post n°2

Re: k math help

by Dogs>Cats 2013-10-14, 08:08

(x^2-1)^n is ur series in ez terms (note when n= 0 the numba will always be 1, dont gimme that 0^0 stuff its not relevant Very Happy

Very Happy

)
x= 1/2
r = (.5^2-1)
.25 - 1
-.75
converges if -1 < r < 1
r = -.75
first term /( 1 -r)
(-.75^0)/(1--.75)

1/1.75 is ur answer
OT dont think im dum cuz i asked u what question u needed lol i didnt see it :3

The Uzumaki

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Post n°3

Re: k math help

by The Uzumaki 2013-10-14, 08:22

Dogs>Cats wrote:(x^2-1)^n is ur series in ez terms (note when n= 0 the numba will always be 1, dont gimme that 0^0 stuff its not relevant )
x= 1/2
r = (.5^2-1)
.25 - 1
-.75
converges if -1 < r < 1
r = -.75
first term /( 1 -r)
(-.75^0)/(1--.75)

1/1.75 is ur answer
OT dont think im dum cuz i asked u what question u needed lol i didnt see it :3

Why would I think you're dumb <3

But they want us to find set values of x before substituting x equals 0.5 you did the second part before the first and used that answer. ..

But

The Uzumaki

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Post n°4

Re: k math help

by The Uzumaki 2013-10-14, 08:29

1 - l (x^2 - 1) l< 0

l (x^2 - 1) l < 1

remove the modulus by squaring both sides,

x^2 - 1 < 1
x^2 < 2
x < + - root of 2

- root 2 < x < root 2 ?

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Post n°5

Re: k math help

by Dogs>Cats 2013-10-14, 08:58

r = (x^2-1)
it converges if x if -1 < x < 1
to find the point
first term/(1-r)
1/(1-(x^2-1))
1/(1+ -(x^2) +1)
so most simplified is
1/(2+-(x^2))
[remeber that when u do stuff like 1-(a+b) u open the paranthathes or however u spell (), im not a good speller, its 1+ -a -b
so when u put in 1/2 for x its 0.5^2 = 0.25
then u have to multiply by negative 1
1+ -.25 + 1
= 1/1.75
= what i said
PS
dont know where ur going off of on the above post sorry >.<

Last edited by Dogs>Cats on 2013-10-14, 09:07; edited 3 times in total

sai karthik4

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Post n°6

Re: k math help

by sai karthik4 2013-10-14, 08:58

what the fuck? which book?

The Uzumaki

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Post n°7

Re: k math help

by The Uzumaki 2013-10-14, 09:31

where tyhe question says "and the value of s when x = 0.5" I want you to cancel that

imagine that's not part of the question. question is only till the comma

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Post n°8

Re: k math help

by Dogs>Cats 2013-10-14, 09:32

r = (x^2-1)
it converges if x if -1 < x < 1
to find the point
first term/(1-r)
1/(1-(x^2-1))
1/(1+ -(x^2) +1)
so most simplified is
1/(2+-(x^2))

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Post n°9

Re: k math help

by Iamtaba 2013-10-15, 07:28

I thought it converges if |r|<1
meaning -1<r<1,where r is what you multiply per term
so -1<x^2-1<1
meaning - i)sqrt of 2<x <sqrt of 2
formula for value=a(first term)/1-r,and x=1/2
so r=1/2^2-1=-3/4,and a=1
so a/1-(-3/4)=1/7/4=ii)4/7

Sand Crawl99 | Z4S

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Post n°10

Re: k math help

by Sand Crawl99 | Z4S 2013-10-15, 10:11

Its an easy question i wont contribute and waste time .

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Post n°11

Re: k math help

by G 2013-10-15, 11:55

And I struggled doing Algebra homework last night.

The Uzumaki

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Post n°12

Re: k math help

by The Uzumaki 2013-10-15, 12:17

Should have changed title to "meth help" and watch the replies

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Post n°13

Re: k math help

by Sanne 2013-10-15, 12:20

I'm also stuck with math, can someone help me out. It's not that hard but i just don't see it:

Given:
y1(t) = 1-e^-0,35t
y2(t) = e^-0,35t

Solve: y1(t) = y2(t)

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Post n°14

Re: k math help

by Sanne 2013-10-15, 12:31

Sanne wrote:I'm also stuck with math, can someone help me out. It's not that hard but i just don't see it:

Given:
y1(t) = 1-e^-0,35t
y2(t) = e^-0,35t

Solve: y1(t) = y2(t)

nvm got it, had the - wrong:

1 = 2e^-0,35t ( i had 1 = 0 )
,5 = e^-0,35t
ln(.5) = -,35t
t = ln(.5)/-.35 = 1,98

derp.

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Post n°15

Re: k math help

by Dogs>Cats 2013-10-15, 19:20

Iamtaba wrote:I thought it converges if |r|<1
meaning -1<r<1,where r is what you multiply per term
so -1<x^2-1<1
meaning - i)sqrt of 2<x <sqrt of 2
formula for value=a(first term)/1-r,and x=1/2
so r=1/2^2-1=-3/4,and a=1
so a/1-(-3/4)=1/7/4=ii)4/7

if u wanted to remove the square in x^2 u have to factor not just sq rt each term
edit
where the hell did the 2 come from actually

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Post n°16

Re: k math help

by Shygodd 2013-10-15, 20:43

How i felt reading this thread

Spoiler:

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Post n°17

Re: k math help

by Dubiously 2013-10-16, 00:26

k math help Nrbb

Wand wrote:^ Squares can have two roots.

So, it would be -√2 < x < 0 or 0 < x < √2

Personally, I'd have done it likeeeee:
Spoiler:

Smile

Last edited by Dubiously on 2013-10-16, 01:04; edited 1 time in total

Tom's Slave

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Post n°18

Re: k math help

by Tom's Slave 2013-10-16, 00:31

Dubiously wrote:

Can we be friends?

Wand

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Post n°19

Re: k math help

by Wand 2013-10-16, 00:52

^ Squares can have two roots.

So, it would be -√2 < x < 0 or 0 < x < √2

Personally, I'd have done it likeeeee:

Spoiler:

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Post n°20

Re: k math help

by Daft Punk 2013-10-16, 00:52

Rand

Wand

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Post n°21

Re: k math help

by Wand 2013-10-16, 00:56

Daft Punk wrote:Rand

I am i am i am. Sad

Sad

The Uzumaki

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Post n°22

Re: k math help

by The Uzumaki 2013-10-16, 04:04

Dubiously wrote:

Wand wrote:^ Squares can have two roots.

So, it would be -√2 < x < 0 or 0 < x < √2

Personally, I'd have done it likeeeee:
Spoiler:

you know what, even though it was already solved, I truly appreciate that as you're the one who actually read what I said when I asked for handwritten working and you posted a picture for me <3

Also yes, after checking with the answers the range of x required both + and - roots Smile

Smile

Thanks again^^

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Post n°23

Re: k math help

by Dogs>Cats 2013-10-16, 08:36

Doodle wrote:

Dubiously wrote:

Wand wrote:^ Squares can have two roots.

So, it would be -√2 < x < 0 or 0 < x < √2

Personally, I'd have done it likeeeee:
Spoiler:

you know what, even though it was already solved, I truly appreciate that as you're the one who actually read what I said when I asked for handwritten working and you posted a picture for me <3

Also yes, after checking with the answers the range of x required both + and - roots

Thanks again^^

scammeur i solved first and i didnt get a thanks

The Uzumaki

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Post n°24

Re: k math help

by The Uzumaki 2013-10-16, 08:38

Dogs>Cats wrote:

Doodle wrote:

Dubiously wrote:

Wand wrote:^ Squares can have two roots.

So, it would be -√2 < x < 0 or 0 < x < √2

Personally, I'd have done it likeeeee:
Spoiler:

you know what, even though it was already solved, I truly appreciate that as you're the one who actually read what I said when I asked for handwritten working and you posted a picture for me <3

Also yes, after checking with the answers the range of x required both + and - roots

Thanks again^^

scammeur i solved first and i didnt get a thanks

thanked you on irc

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Post n°25

Re: k math help

by Sanne 2013-10-16, 10:07

doodle we have the same math we are like family

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Post n°26

Re: k math help

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